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[Docs] Clarify functionality of update_tri_layer_state (#10370)
* Add information to docs - If layer z is not a higher layer than both x and y, the layer change code does not function correctly. * Update docs/ref_functions.md * Update docs/ref_functions.md * Update docs/ref_functions.md
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@ -43,7 +43,9 @@ bool process_record_user(uint16_t keycode, keyrecord_t *record) {
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### `update_tri_layer_state(state, x, y, z)`
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### `update_tri_layer_state(state, x, y, z)`
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The other function is `update_tri_layer_state(state, x, y, z)`. This function is meant to be called from the [`layer_state_set_*` functions](custom_quantum_functions.md#layer-change-code). This means that any time that you use a keycode to change the layer, this will be checked. So you could use `LT(layer, kc)` to change the layer and it will trigger the same layer check.
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The other function is `update_tri_layer_state(state, x, y, z)`. This function is meant to be called from the [`layer_state_set_*` functions](custom_quantum_functions.md#layer-change-code). This means that any time that you use a keycode to change the layer, this will be checked. So you could use `LT(layer, kc)` to change the layer and it will trigger the same layer check.
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The caveat to this method is that you cannot access the `z` layer without having `x` and `y` layers on, since if you try to activate just layer `z`, it will run this code and turn off layer `z` before you could use it.
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There are a couple of caveats to this method:
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1. You cannot access the `z` layer without having `x` and `y` layers on, since if you try to activate just layer `z`, it will run this code and turn off layer `z` before you could use it.
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2. Because layers are processed from the highest number `z` should be a higher layer than `x` and `y` or you may not be able to access it.
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#### Example
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#### Example
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